(x+2)(x+3)=x2+4x+13

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Solution for (x+2)(x+3)=x2+4x+13 equation: 



(x+2)(x+3)=x2+4x+13

We move all terms to the left:

(x+2)(x+3)-(x2+4x+13)=0

We add all the numbers together, and all the variables

-(+x^2+4x+13)+(x+2)(x+3)=0

We get rid of parentheses

-x^2-4x+(x+2)(x+3)-13=0

We multiply parentheses ..

-x^2+(+x^2+3x+2x+6)-4x-13=0

We add all the numbers together, and all the variables

-1x^2+(+x^2+3x+2x+6)-4x-13=0

We get rid of parentheses

-1x^2+x^2+3x+2x-4x+6-13=0

We add all the numbers together, and all the variables

x-7=0

We move all terms containing x to the left, all other terms to the right

x=7

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