(20+2x)(30+2x)=V(x)

Solution for (20+2x)(30+2x)=V(x) equation:

(20+2x)(30+2x)=(x)

We move all terms to the left:

(20+2x)(30+2x)-((x))=0

determiningTheFunctionDomain
(20+2x)(30+2x)-x=0

We add all the numbers together, and all the variables

(2x+20)(2x+30)-x=0

We add all the numbers together, and all the variables

-1x+(2x+20)(2x+30)=0

We multiply parentheses ..

(+4x^2+60x+40x+600)-1x=0

We get rid of parentheses

4x^2+60x+40x-1x+600=0

We add all the numbers together, and all the variables

4x^2+99x+600=0

a = 4; b = 99; c = +600;
Δ = b2-4ac
Δ = 992-4·4·600
Δ = 201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(99)-\sqrt{201}}{2*4}=\frac{-99-\sqrt{201}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(99)+\sqrt{201}}{2*4}=\frac{-99+\sqrt{201}}{8}
$