6(2x+5)=1/2(24x+4)+3

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Solution for 6(2x+5)=1/2(24x+4)+3 equation:



6(2x+5)=1/2(24x+4)+3
We move all terms to the left:
6(2x+5)-(1/2(24x+4)+3)=0
Domain of the equation: 2(24x+4)+3)!=0
x∈R
We multiply parentheses
12x-(1/2(24x+4)+3)+30=0
We multiply all the terms by the denominator
12x*2(24x+4)+30*2(24x+4)+3)-(1+3)=0
We add all the numbers together, and all the variables
12x*2(24x+4)+30*2(24x+4)+3)-4=0
We add all the numbers together, and all the variables
12x*2(24x+4)+30*2(24x+4)=0
Wy multiply elements
24x^2(2+60x(2=0

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