(2/3)x+0.25x=x+2

Solution for (2/3)x+0.25x=x+2 equation:

(2/3)x+0.25x=x+2

We move all terms to the left:

(2/3)x+0.25x-(x+2)=0


Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+2/3)x+0.25x-(x+2)=0

We add all the numbers together, and all the variables

0.25x+(+2/3)x-(x+2)=0

We multiply parentheses

2x^2+0.25x-(x+2)=0

We get rid of parentheses

2x^2+0.25x-x-2=0

We add all the numbers together, and all the variables

2x^2-0.75x-2=0

a = 2; b = -0.75; c = -2;
Δ = b2-4ac
Δ = -0.752-4·2·(-2)
Δ = 16.5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.75)-\sqrt{16.5625}}{2*2}=\frac{0.75-\sqrt{16.5625}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.75)+\sqrt{16.5625}}{2*2}=\frac{0.75+\sqrt{16.5625}}{4}
$