(2/3)w=1/2

Solution for (2/3)w=1/2 equation:

(2/3)w=1/2

We move all terms to the left:

(2/3)w-(1/2)=0


Domain of the equation: 3)w!=0

w!=0/1

w!=0

w∈R


We add all the numbers together, and all the variables

(+2/3)w-(+1/2)=0

We multiply parentheses

2w^2-(+1/2)=0

We get rid of parentheses

2w^2-1/2=0

We multiply all the terms by the denominator


2w^2*2-1=0

Wy multiply elements

4w^2-1=0

a = 4; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·4·(-1)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4}{2*4}=\frac{-4}{8}
=-1/2
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4}{2*4}=\frac{4}{8}
=1/2
$