5/3(5x+9)=+4/5(1-9x)=

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Solution for 5/3(5x+9)=+4/5(1-9x)= equation: 



5/3(5x+9)=+4/5(1-9x)=

We move all terms to the left:

5/3(5x+9)-(+4/5(1-9x))=0



Domain of the equation: 3(5x+9)!=0

x∈R





Domain of the equation: 5(1-9x))!=0

x∈R



We add all the numbers together, and all the variables

5/3(5x+9)-(+4/5(-9x+1))=0

We calculate fractions


(25x(-)/(3(5x+9)*5(-9x+1)))+(-12x5/(3(5x+9)*5(-9x+1)))=0



We calculate terms in parentheses: +(25x(-)/(3(5x+9)*5(-9x+1))), so:

25x(-)/(3(5x+9)*5(-9x+1))

We add all the numbers together, and all the variables

25x0/(3(5x+9)*5(-9x+1))

We multiply all the terms by the denominator


25x0

We add all the numbers together, and all the variables

25x

Back to the equation:

+(25x)





We calculate terms in parentheses: +(-12x5/(3(5x+9)*5(-9x+1))), so:

-12x5/(3(5x+9)*5(-9x+1))

We multiply all the terms by the denominator


-12x5

We add all the numbers together, and all the variables

-12x^5

We do not support expression: x^5

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