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50x+4x^2+(25x)=166
We move all terms to the left:
50x+4x^2+(25x)-(166)=0
We add all the numbers together, and all the variables
4x^2+75x-166=0
a = 4; b = 75; c = -166;
Δ = b2-4ac
Δ = 752-4·4·(-166)
Δ = 8281
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8281}=91$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(75)-91}{2*4}=\frac{-166}{8} =-20+3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(75)+91}{2*4}=\frac{16}{8} =2 $
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