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(2/3)-(k-8)=52
We move all terms to the left:
(2/3)-(k-8)-(52)=0
determiningTheFunctionDomain -(k-8)-52+(2/3)=0
We add all the numbers together, and all the variables
-(k-8)-52+(+2/3)=0
We get rid of parentheses
-k+8-52+2/3=0
We multiply all the terms by the denominator
-k*3+2+8*3-52*3=0
We add all the numbers together, and all the variables
-k*3-130=0
Wy multiply elements
-3k-130=0
We move all terms containing k to the left, all other terms to the right
-3k=130
k=130/-3
k=-43+1/3
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