3d(d-3)+5(d+7)-d(d+1)-2(d-3)(d+3)+4=0

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Solution for 3d(d-3)+5(d+7)-d(d+1)-2(d-3)(d+3)+4=0 equation:



3d(d-3)+5(d+7)-d(d+1)-2(d-3)(d+3)+4=0
We use the square of the difference formula
d^2+3d(d-3)+5(d+7)-d(d+1)+9+4=0
We multiply parentheses
d^2+3d^2-d^2-9d+5d-d+35+9+4=0
We add all the numbers together, and all the variables
3d^2-5d+48=0
a = 3; b = -5; c = +48;
Δ = b2-4ac
Δ = -52-4·3·48
Δ = -551
Delta is less than zero, so there is no solution for the equation

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