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(2/3)+(3m/5)=(31/15)
We move all terms to the left:
(2/3)+(3m/5)-((31/15))=0
We add all the numbers together, and all the variables
(+3m/5)+(+2/3)-((+31/15))=0
We get rid of parentheses
3m/5+2/3-((+31/15))=0
We calculate fractions
135m^2/()+()/()+()/()=0
We add all the numbers together, and all the variables
135m^2/()+2=0
We multiply all the terms by the denominator
135m^2+2*()=0
We add all the numbers together, and all the variables
135m^2=0
a = 135; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·135·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$m=\frac{-b}{2a}=\frac{0}{270}=0$
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