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3(3x-6)=3(x-2)
We move all terms to the left:
3(3x-6)-(3(x-2))=0
We multiply parentheses
9x-(3(x-2))-18=0
We calculate terms in parentheses: -(3(x-2)), so:We get rid of parentheses
3(x-2)
We multiply parentheses
3x-6
Back to the equation:
-(3x-6)
9x-3x+6-18=0
We add all the numbers together, and all the variables
6x-12=0
We move all terms containing x to the left, all other terms to the right
6x=12
x=12/6
x=2
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