(23)5(x-2)+x=6(x+3)-4x

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Solution for (23)5(x-2)+x=6(x+3)-4x equation: 



(23)5(x-2)+x=6(x+3)-4x

We move all terms to the left:

(23)5(x-2)+x-(6(x+3)-4x)=0

We add all the numbers together, and all the variables

x+235(x-2)-(6(x+3)-4x)=0

We multiply parentheses

x+235x-(6(x+3)-4x)-470=0



We calculate terms in parentheses: -(6(x+3)-4x), so:

6(x+3)-4x

We add all the numbers together, and all the variables

-4x+6(x+3)

We multiply parentheses

-4x+6x+18

We add all the numbers together, and all the variables

2x+18

Back to the equation:

-(2x+18)



We add all the numbers together, and all the variables

236x-(2x+18)-470=0

We get rid of parentheses

236x-2x-18-470=0

We add all the numbers together, and all the variables

234x-488=0

We move all terms containing x to the left, all other terms to the right

234x=488

x=488/234

x=2+10/117

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