(2/3)(n-6)=5n-43

Solution for (2/3)(n-6)=5n-43 equation:

(2/3)(n-6)=5n-43

We move all terms to the left:

(2/3)(n-6)-(5n-43)=0


Domain of the equation: 3)(n-6)!=0

n∈R


We add all the numbers together, and all the variables

(+2/3)(n-6)-(5n-43)=0

We get rid of parentheses

(+2/3)(n-6)-5n+43=0

We multiply parentheses ..

(+2n^2+2/3*-6)-5n+43=0

We multiply all the terms by the denominator


(+2n^2+2-5n*3*-6)+43*3*-6)=0

We add all the numbers together, and all the variables

(+2n^2+2-5n*3*-6)=0

We get rid of parentheses

2n^2-5n*3*+2-6=0

We add all the numbers together, and all the variables

2n^2-5n*3*-4=0

Wy multiply elements

2n^2-15n^2-4=0

We add all the numbers together, and all the variables

-13n^2-4=0

a = -13; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·(-13)·(-4)
Δ = -208
Delta is less than zero, so there is no solution for the equation