100(6x-10)=20(1,720+100x)

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Solution for 100(6x-10)=20(1,720+100x) equation: 



100(6x-10)=20(1.720+100x)

We move all terms to the left:

100(6x-10)-(20(1.720+100x))=0

We add all the numbers together, and all the variables

100(6x-10)-(20(100x+1.72))=0

We multiply parentheses

600x-(20(100x+1.72))-1000=0



We calculate terms in parentheses: -(20(100x+1.72)), so:

20(100x+1.72)

We multiply parentheses

2000x+34.4

Back to the equation:

-(2000x+34.4)



We get rid of parentheses

600x-2000x-34.4-1000=0

We add all the numbers together, and all the variables

-1400x-1034.4=0

We move all terms containing x to the left, all other terms to the right

-1400x=1034.4

x=1034.4/-1400

x=-430.99999999998/583.33333333331

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