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(2/3)n=5n-39
We move all terms to the left:
(2/3)n-(5n-39)=0
Domain of the equation: 3)n!=0We add all the numbers together, and all the variables
n!=0/1
n!=0
n∈R
(+2/3)n-(5n-39)=0
We multiply parentheses
2n^2-(5n-39)=0
We get rid of parentheses
2n^2-5n+39=0
a = 2; b = -5; c = +39;
Δ = b2-4ac
Δ = -52-4·2·39
Δ = -287
Delta is less than zero, so there is no solution for the equation
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