(1y+5)-(4y-3)=1y+64

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Solution for (1y+5)-(4y-3)=1y+64 equation: 



(1y+5)-(4y-3)=1y+64

We move all terms to the left:

(1y+5)-(4y-3)-(1y+64)=0

We add all the numbers together, and all the variables

(y+5)-(4y-3)-(y+64)=0

We get rid of parentheses

y-4y-y+5+3-64=0

We add all the numbers together, and all the variables

-4y-56=0

We move all terms containing y to the left, all other terms to the right

-4y=56

y=56/-4

y=-14

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