(1x/2x)+10=(1x/4x)+54

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Solution for (1x/2x)+10=(1x/4x)+54 equation: 



(1x/2x)+10=(1x/4x)+54

We move all terms to the left:

(1x/2x)+10-((1x/4x)+54)=0



Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 4x)+54)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1x/2x)-((+1x/4x)+54)+10=0

We get rid of parentheses

1x/2x-((+1x/4x)+54)+10=0

We calculate fractions


4x^2/8x^2+(-((+1x*2x)/8x^2+10=0

We calculate fractions

We do not support expression: x^4

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