2/3(3x+9)=16

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Solution for 2/3(3x+9)=16 equation: 



2/3(3x+9)=16

We move all terms to the left:

2/3(3x+9)-(16)=0



Domain of the equation: 3(3x+9)!=0

x∈R



We multiply all the terms by the denominator


-16*3(3x+9)+2=0

Wy multiply elements

-48x(3+2=0

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