3(2x-4)-(x+3)=-2(x+3)+3(x+1)+4x

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Solution for 3(2x-4)-(x+3)=-2(x+3)+3(x+1)+4x equation:



3(2x-4)-(x+3)=-2(x+3)+3(x+1)+4x
We move all terms to the left:
3(2x-4)-(x+3)-(-2(x+3)+3(x+1)+4x)=0
We multiply parentheses
6x-(x+3)-(-2(x+3)+3(x+1)+4x)-12=0
We get rid of parentheses
6x-x-(-2(x+3)+3(x+1)+4x)-3-12=0
We calculate terms in parentheses: -(-2(x+3)+3(x+1)+4x), so:
-2(x+3)+3(x+1)+4x
We add all the numbers together, and all the variables
4x-2(x+3)+3(x+1)
We multiply parentheses
4x-2x+3x-6+3
We add all the numbers together, and all the variables
5x-3
Back to the equation:
-(5x-3)
We add all the numbers together, and all the variables
5x-(5x-3)-15=0
We get rid of parentheses
5x-5x+3-15=0
We add all the numbers together, and all the variables
-12!=0
There is no solution for this equation

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