(16x-4)=((9x-6)+58)

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Solution for (16x-4)=((9x-6)+58) equation:



(16x-4)=((9x-6)+58)
We move all terms to the left:
(16x-4)-(((9x-6)+58))=0
We get rid of parentheses
16x-(((9x-6)+58))-4=0
We calculate terms in parentheses: -(((9x-6)+58)), so:
((9x-6)+58)
We calculate terms in parentheses: +((9x-6)+58), so:
(9x-6)+58
We get rid of parentheses
9x-6+58
We add all the numbers together, and all the variables
9x+52
Back to the equation:
+(9x+52)
We get rid of parentheses
9x+52
Back to the equation:
-(9x+52)
We get rid of parentheses
16x-9x-52-4=0
We add all the numbers together, and all the variables
7x-56=0
We move all terms containing x to the left, all other terms to the right
7x=56
x=56/7
x=8

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