2x+3(x-2)=6(x-1)+x

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Solution for 2x+3(x-2)=6(x-1)+x equation: 



2x+3(x-2)=6(x-1)+x

We move all terms to the left:

2x+3(x-2)-(6(x-1)+x)=0

We multiply parentheses

2x+3x-(6(x-1)+x)-6=0



We calculate terms in parentheses: -(6(x-1)+x), so:

6(x-1)+x

We add all the numbers together, and all the variables

x+6(x-1)

We multiply parentheses

x+6x-6

We add all the numbers together, and all the variables

7x-6

Back to the equation:

-(7x-6)



We add all the numbers together, and all the variables

5x-(7x-6)-6=0

We get rid of parentheses

5x-7x+6-6=0

We add all the numbers together, and all the variables

-2x=0

x=0/-2

x=0

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