3(x-20)-4(x+40)=10-6(x-5)

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Solution for 3(x-20)-4(x+40)=10-6(x-5) equation: 



3(x-20)-4(x+40)=10-6(x-5)

We move all terms to the left:

3(x-20)-4(x+40)-(10-6(x-5))=0

We multiply parentheses

3x-4x-(10-6(x-5))-60-160=0



We calculate terms in parentheses: -(10-6(x-5)), so:

10-6(x-5)

determiningTheFunctionDomain
-6(x-5)+10

We multiply parentheses

-6x+30+10

We add all the numbers together, and all the variables

-6x+40

Back to the equation:

-(-6x+40)



We add all the numbers together, and all the variables

-1x-(-6x+40)-220=0

We get rid of parentheses

-1x+6x-40-220=0

We add all the numbers together, and all the variables

5x-260=0

We move all terms containing x to the left, all other terms to the right

5x=260

x=260/5

x=52

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