1/8(t-3)+3/8(t+2)=t-2

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Solution for 1/8(t-3)+3/8(t+2)=t-2 equation: 



1/8(t-3)+3/8(t+2)=t-2

We move all terms to the left:

1/8(t-3)+3/8(t+2)-(t-2)=0



Domain of the equation: 8(t-3)!=0

t∈R





Domain of the equation: 8(t+2)!=0

t∈R



We get rid of parentheses

1/8(t-3)+3/8(t+2)-t+2=0

We calculate fractions


-t+(8tt/(8(t-3)*8(t+2))+(24tt/(8(t-3)*8(t+2))+2=0

We can not solve this equation

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