-6(y-3)=-8y+14

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Solution for -6(y-3)=-8y+14 equation: 



-6(y-3)=-8y+14

We move all terms to the left:

-6(y-3)-(-8y+14)=0

We multiply parentheses

-6y-(-8y+14)+18=0

We get rid of parentheses

-6y+8y-14+18=0

We add all the numbers together, and all the variables

2y+4=0

We move all terms containing y to the left, all other terms to the right

2y=-4

y=-4/2

y=-2

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