(15x-12)+(6x)+(19x+2)=180

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Solution for (15x-12)+(6x)+(19x+2)=180 equation: 



(15x-12)+(6x)+(19x+2)=180

We move all terms to the left:

(15x-12)+(6x)+(19x+2)-(180)=0

We add all the numbers together, and all the variables

6x+(15x-12)+(19x+2)-180=0

We get rid of parentheses

6x+15x+19x-12+2-180=0

We add all the numbers together, and all the variables

40x-190=0

We move all terms containing x to the left, all other terms to the right

40x=190

x=190/40

x=4+3/4

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