(7x-2)+(4x)+(5x-10)=180

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Solution for (7x-2)+(4x)+(5x-10)=180 equation: 



(7x-2)+(4x)+(5x-10)=180

We move all terms to the left:

(7x-2)+(4x)+(5x-10)-(180)=0

We add all the numbers together, and all the variables

4x+(7x-2)+(5x-10)-180=0

We get rid of parentheses

4x+7x+5x-2-10-180=0

We add all the numbers together, and all the variables

16x-192=0

We move all terms containing x to the left, all other terms to the right

16x=192

x=192/16

x=12

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