(13x+4)+(10x-1)=141

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Solution for (13x+4)+(10x-1)=141 equation: 



(13x+4)+(10x-1)=141

We move all terms to the left:

(13x+4)+(10x-1)-(141)=0

We get rid of parentheses

13x+10x+4-1-141=0

We add all the numbers together, and all the variables

23x-138=0

We move all terms containing x to the left, all other terms to the right

23x=138

x=138/23

x=6

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