(3x-1)/2=(4x+2)/3+(1)

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Solution for (3x-1)/2=(4x+2)/3+(1) equation: 



(3x-1)/2=(4x+2)/3+(1)

We move all terms to the left:

(3x-1)/2-((4x+2)/3+(1))=0

We calculate fractions


(9x-3)/()+(-((4x+2)*2)/()=0



We calculate terms in parentheses: +(-((4x+2)*2)/(), so:

-((4x+2)*2)/(

We multiply all the terms by the denominator


-((4x+2)*2)



We calculate terms in parentheses: -((4x+2)*2), so:

(4x+2)*2

We multiply parentheses

8x+4

Back to the equation:

-(8x+4)



We get rid of parentheses

-8x-4

Back to the equation:

+(-8x-4)



We get rid of parentheses

(9x-3)/()-8x-4=0

We multiply all the terms by the denominator


(9x-3)-8x*()-4*()=0

We add all the numbers together, and all the variables

(9x-3)-8x*()=0

We get rid of parentheses

9x-8x*()-3=0

We move all terms containing x to the left, all other terms to the right

9x-8x*()=3

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