0.5(10f-20)-2f=f+2

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Solution for 0.5(10f-20)-2f=f+2 equation: 



0.5(10f-20)-2f=f+2

We move all terms to the left:

0.5(10f-20)-2f-(f+2)=0

We add all the numbers together, and all the variables

-2f+0.5(10f-20)-(f+2)=0

We multiply parentheses

-2f+5f-(f+2)-10=0

We get rid of parentheses

-2f+5f-f-2-10=0

We add all the numbers together, and all the variables

2f-12=0

We move all terms containing f to the left, all other terms to the right

2f=12

f=12/2

f=6

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