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(12x)(x+2)=960
We move all terms to the left:
(12x)(x+2)-(960)=0
We multiply parentheses
12x^2+24x-960=0
a = 12; b = 24; c = -960;
Δ = b2-4ac
Δ = 242-4·12·(-960)
Δ = 46656
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{46656}=216$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-216}{2*12}=\frac{-240}{24} =-10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+216}{2*12}=\frac{192}{24} =8 $
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