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3/4x-5=3x-16
We move all terms to the left:
3/4x-5-(3x-16)=0
Domain of the equation: 4x!=0We get rid of parentheses
x!=0/4
x!=0
x∈R
3/4x-3x+16-5=0
We multiply all the terms by the denominator
-3x*4x+16*4x-5*4x+3=0
Wy multiply elements
-12x^2+64x-20x+3=0
We add all the numbers together, and all the variables
-12x^2+44x+3=0
a = -12; b = 44; c = +3;
Δ = b2-4ac
Δ = 442-4·(-12)·3
Δ = 2080
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2080}=\sqrt{16*130}=\sqrt{16}*\sqrt{130}=4\sqrt{130}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-4\sqrt{130}}{2*-12}=\frac{-44-4\sqrt{130}}{-24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+4\sqrt{130}}{2*-12}=\frac{-44+4\sqrt{130}}{-24} $
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