-2(3-8x)-(1-7x)=2(3x-1)+4(2+x)

Solution for -2(3-8x)-(1-7x)=2(3x-1)+4(2+x) equation:

-2(3-8x)-(1-7x)=2(3x-1)+4(2+x)

We move all terms to the left:

-2(3-8x)-(1-7x)-(2(3x-1)+4(2+x))=0

We add all the numbers together, and all the variables

-2(-8x+3)-(-7x+1)-(2(3x-1)+4(x+2))=0

We multiply parentheses

16x-(-7x+1)-(2(3x-1)+4(x+2))-6=0

We get rid of parentheses

16x+7x-(2(3x-1)+4(x+2))-1-6=0


We calculate terms in parentheses: -(2(3x-1)+4(x+2)), so:

2(3x-1)+4(x+2)

We multiply parentheses

6x+4x-2+8

We add all the numbers together, and all the variables

10x+6

Back to the equation:

-(10x+6)


We add all the numbers together, and all the variables

23x-(10x+6)-7=0

We get rid of parentheses

23x-10x-6-7=0

We add all the numbers together, and all the variables

13x-13=0

We move all terms containing x to the left, all other terms to the right

13x=13

x=13/13

x=1