(12+x)/4=(-6-x)/2

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Solution for (12+x)/4=(-6-x)/2 equation: 



(12+x)/4=(-6-x)/2

We move all terms to the left:

(12+x)/4-((-6-x)/2)=0

We add all the numbers together, and all the variables

(x+12)/4-((-1x-6)/2)=0

We calculate fractions


x/()+(-((-1x-6)*4)/()=0



We calculate terms in parentheses: +(-((-1x-6)*4)/(), so:

-((-1x-6)*4)/(

We multiply all the terms by the denominator


-((-1x-6)*4)



We calculate terms in parentheses: -((-1x-6)*4), so:

(-1x-6)*4

We multiply parentheses

-4x-24

Back to the equation:

-(-4x-24)



We get rid of parentheses

4x+24

Back to the equation:

+(4x+24)



We get rid of parentheses

x/()+4x+24=0

We multiply all the terms by the denominator


x+4x*()+24*()=0

We add all the numbers together, and all the variables

x+4x*()=0

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