4(v-5)-3=-4(-4+2)-3v

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Solution for 4(v-5)-3=-4(-4+2)-3v equation: 



4(v-5)-3=-4(-4+2)-3v

We move all terms to the left:

4(v-5)-3-(-4(-4+2)-3v)=0

We add all the numbers together, and all the variables

4(v-5)-(-4(-2)-3v)-3=0

We multiply parentheses

4v-(-4(-2)-3v)-20-3=0



We calculate terms in parentheses: -(-4(-2)-3v), so:

-4(-2)-3v

determiningTheFunctionDomain
-3v-4(-2)

We add all the numbers together, and all the variables

-3v+8

Back to the equation:

-(-3v+8)



We add all the numbers together, and all the variables

4v-(-3v+8)-23=0

We get rid of parentheses

4v+3v-8-23=0

We add all the numbers together, and all the variables

7v-31=0

We move all terms containing v to the left, all other terms to the right

7v=31

v=31/7

v=4+3/7

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