2(x-5)+4=6x-3(-x+1)

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Solution for 2(x-5)+4=6x-3(-x+1) equation: 



2(x-5)+4=6x-3(-x+1)

We move all terms to the left:

2(x-5)+4-(6x-3(-x+1))=0

We add all the numbers together, and all the variables

2(x-5)-(6x-3(-1x+1))+4=0

We multiply parentheses

2x-(6x-3(-1x+1))-10+4=0



We calculate terms in parentheses: -(6x-3(-1x+1)), so:

6x-3(-1x+1)

We multiply parentheses

6x+3x-3

We add all the numbers together, and all the variables

9x-3

Back to the equation:

-(9x-3)



We add all the numbers together, and all the variables

2x-(9x-3)-6=0

We get rid of parentheses

2x-9x+3-6=0

We add all the numbers together, and all the variables

-7x-3=0

We move all terms containing x to the left, all other terms to the right

-7x=3

x=3/-7

x=-3/7

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