2/3(6-9x)=-1/5(15x+10)

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Solution for 2/3(6-9x)=-1/5(15x+10) equation: 



2/3(6-9x)=-1/5(15x+10)

We move all terms to the left:

2/3(6-9x)-(-1/5(15x+10))=0



Domain of the equation: 3(6-9x)!=0

x∈R





Domain of the equation: 5(15x+10))!=0

x∈R



We add all the numbers together, and all the variables

2/3(-9x+6)-(-1/5(15x+10))=0

We calculate fractions


(10x1/(3(-9x+6)*5(15x+10)))+(-(-3x0)/(3(-9x+6)*5(15x+10)))=0



We calculate terms in parentheses: +(10x1/(3(-9x+6)*5(15x+10))), so:

10x1/(3(-9x+6)*5(15x+10))

We multiply all the terms by the denominator


10x1

We add all the numbers together, and all the variables

10x

Back to the equation:

+(10x)





We calculate terms in parentheses: +(-(-3x0)/(3(-9x+6)*5(15x+10))), so:

-(-3x0)/(3(-9x+6)*5(15x+10))

We add all the numbers together, and all the variables

-(-3x)/(3(-9x+6)*5(15x+10))

We multiply all the terms by the denominator


-(-3x)

We get rid of parentheses

3x

Back to the equation:

+(3x)



We add all the numbers together, and all the variables

13x=0

x=0/13

x=0

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