(12)(10)=(x+6)(x-1)

Solution for (12)(10)=(x+6)(x-1) equation:

(12)(10)=(x+6)(x-1)

We move all terms to the left:

(12)(10)-((x+6)(x-1))=0

We multiply parentheses ..

-((+x^2-1x+6x-6))+1210=0


We calculate terms in parentheses: -((+x^2-1x+6x-6)), so:

(+x^2-1x+6x-6)

We get rid of parentheses

x^2-1x+6x-6

We add all the numbers together, and all the variables

x^2+5x-6

Back to the equation:

-(x^2+5x-6)


We get rid of parentheses

-x^2-5x+6+1210=0

We add all the numbers together, and all the variables

-1x^2-5x+1216=0

a = -1; b = -5; c = +1216;
Δ = b2-4ac
Δ = -52-4·(-1)·1216
Δ = 4889
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{4889}}{2*-1}=\frac{5-\sqrt{4889}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{4889}}{2*-1}=\frac{5+\sqrt{4889}}{-2}
$