(2/3)s+s=60

Solution for (2/3)s+s=60 equation:

(2/3)s+s=60

We move all terms to the left:

(2/3)s+s-(60)=0


Domain of the equation: 3)s!=0

s!=0/1

s!=0

s∈R


We add all the numbers together, and all the variables

(+2/3)s+s-60=0

We add all the numbers together, and all the variables

s+(+2/3)s-60=0

We multiply parentheses

2s^2+s-60=0

a = 2; b = 1; c = -60;
Δ = b2-4ac
Δ = 12-4·2·(-60)
Δ = 481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{481}}{2*2}=\frac{-1-\sqrt{481}}{4}
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{481}}{2*2}=\frac{-1+\sqrt{481}}{4}
$