Y=10+2(3+4x)

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Solution for Y=10+2(3+4x) equation: 



=10+2(3+4Y)

We move all terms to the left:

-(10+2(3+4Y))=0

We add all the numbers together, and all the variables

-(10+2(4Y+3))=0



We calculate terms in parentheses: -(10+2(4Y+3)), so:

10+2(4Y+3)

determiningTheFunctionDomain
2(4Y+3)+10

We multiply parentheses

8Y+6+10

We add all the numbers together, and all the variables

8Y+16

Back to the equation:

-(8Y+16)



We get rid of parentheses

-8Y-16=0

We move all terms containing Y to the left, all other terms to the right

-8Y=16

Y=16/-8

Y=-2

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