(10x-20)/3=(5x-9)/2

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Solution for (10x-20)/3=(5x-9)/2 equation: 



(10x-20)/3=(5x-9)/2

We move all terms to the left:

(10x-20)/3-((5x-9)/2)=0

We calculate fractions


10x/()+(-((5x-9)*3)/()=0



We calculate terms in parentheses: +(-((5x-9)*3)/(), so:

-((5x-9)*3)/(

We multiply all the terms by the denominator


-((5x-9)*3)



We calculate terms in parentheses: -((5x-9)*3), so:

(5x-9)*3

We multiply parentheses

15x-27

Back to the equation:

-(15x-27)



We get rid of parentheses

-15x+27

Back to the equation:

+(-15x+27)



We get rid of parentheses

10x/()-15x+27=0

We multiply all the terms by the denominator


10x-15x*()+27*()=0

We add all the numbers together, and all the variables

10x-15x*()=0

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