1536=(2x+2)(x-8)(4)

Solution for 1536=(2x+2)(x-8)(4) equation:

1536=(2x+2)(x-8)(4)

We move all terms to the left:

1536-((2x+2)(x-8)(4))=0

We multiply parentheses ..

-((+2x^2-16x+2x-16)4)+1536=0


We calculate terms in parentheses: -((+2x^2-16x+2x-16)4), so:

(+2x^2-16x+2x-16)4

We multiply parentheses

8x^2-64x+8x-64

We add all the numbers together, and all the variables

8x^2-56x-64

Back to the equation:

-(8x^2-56x-64)


We get rid of parentheses

-8x^2+56x+64+1536=0

We add all the numbers together, and all the variables

-8x^2+56x+1600=0

a = -8; b = 56; c = +1600;
Δ = b2-4ac
Δ = 562-4·(-8)·1600
Δ = 54336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{54336}=\sqrt{64*849}=\sqrt{64}*\sqrt{849}=8\sqrt{849}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-8\sqrt{849}}{2*-8}=\frac{-56-8\sqrt{849}}{-16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+8\sqrt{849}}{2*-8}=\frac{-56+8\sqrt{849}}{-16}
$