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1/5b+3=13
We move all terms to the left:
1/5b+3-(13)=0
Domain of the equation: 5b!=0We add all the numbers together, and all the variables
b!=0/5
b!=0
b∈R
1/5b-10=0
We multiply all the terms by the denominator
-10*5b+1=0
Wy multiply elements
-50b+1=0
We move all terms containing b to the left, all other terms to the right
-50b=-1
b=-1/-50
b=1/50
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