(10c-43)+(-c+52)=90

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Solution for (10c-43)+(-c+52)=90 equation: 



(10c-43)+(-c+52)=90

We move all terms to the left:

(10c-43)+(-c+52)-(90)=0

We add all the numbers together, and all the variables

(10c-43)+(-1c+52)-90=0

We get rid of parentheses

10c-1c-43+52-90=0

We add all the numbers together, and all the variables

9c-81=0

We move all terms containing c to the left, all other terms to the right

9c=81

c=81/9

c=9

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