(7z+67)+(3z+132)=159

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Solution for (7z+67)+(3z+132)=159 equation: 



(7z+67)+(3z+132)=159

We move all terms to the left:

(7z+67)+(3z+132)-(159)=0

We get rid of parentheses

7z+3z+67+132-159=0

We add all the numbers together, and all the variables

10z+40=0

We move all terms containing z to the left, all other terms to the right

10z=-40

z=-40/10

z=-4

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