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(-2/3x-7)-(-12+1/6x)=
We move all terms to the left:
(-2/3x-7)-(-12+1/6x)-()=0
Domain of the equation: 3x-7)!=0
x∈R
Domain of the equation: 6x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(-2/3x-7)-(1/6x-12)-()=0
We add all the numbers together, and all the variables
(-2/3x-7)-(1/6x-12)=0
We get rid of parentheses
-2/3x-1/6x-7+12=0
We calculate fractions
(-12x)/18x^2+(-3x)/18x^2-7+12=0
We add all the numbers together, and all the variables
(-12x)/18x^2+(-3x)/18x^2+5=0
We multiply all the terms by the denominator
(-12x)+(-3x)+5*18x^2=0
Wy multiply elements
90x^2+(-12x)+(-3x)=0
We get rid of parentheses
90x^2-12x-3x=0
We add all the numbers together, and all the variables
90x^2-15x=0
a = 90; b = -15; c = 0;
Δ = b2-4ac
Δ = -152-4·90·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-15}{2*90}=\frac{0}{180} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+15}{2*90}=\frac{30}{180} =1/6 $
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