(6m+28)+(7m+54)=(2m+104)

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Solution for (6m+28)+(7m+54)=(2m+104) equation: 



(6m+28)+(7m+54)=(2m+104)

We move all terms to the left:

(6m+28)+(7m+54)-((2m+104))=0

We get rid of parentheses

6m+7m-((2m+104))+28+54=0



We calculate terms in parentheses: -((2m+104)), so:

(2m+104)

We get rid of parentheses

2m+104

Back to the equation:

-(2m+104)



We add all the numbers together, and all the variables

13m-(2m+104)+82=0

We get rid of parentheses

13m-2m-104+82=0

We add all the numbers together, and all the variables

11m-22=0

We move all terms containing m to the left, all other terms to the right

11m=22

m=22/11

m=2

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