(1/6)(x-5)=(1/2)(x+6)

Solution for (1/6)(x-5)=(1/2)(x+6) equation:

(1/6)(x-5)=(1/2)(x+6)

We move all terms to the left:

(1/6)(x-5)-((1/2)(x+6))=0


Domain of the equation: 6)(x-5)!=0

x∈R



Domain of the equation: 2)(x+6))!=0

x∈R


We add all the numbers together, and all the variables

(+1/6)(x-5)-((+1/2)(x+6))=0

We multiply parentheses ..

(+x^2+1/6*-5)-((+1/2)(x+6))=0

We calculate fractions


((+x^2+1*2)(x+6)))/(-5)*2)(x+6))+6*)+()/(-5)*2)(x+6))+6*)=0

We calculate fractions


(((+x^2+1*2)(x+6)))*(-5)*2)(x+6))+6*))/((*(-5)*2)x)+(-5)*2)(x+6))+6*)+()*()/((*(-5)*2)x)=0

We can not solve this equation