3b+(b-3b)=12

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Solution for 3b+(b-3b)=12 equation: 



3b+(b-3b)=12

We move all terms to the left:

3b+(b-3b)-(12)=0

We add all the numbers together, and all the variables

3b+(-2b)-12=0

We get rid of parentheses

3b-2b-12=0

We add all the numbers together, and all the variables

b-12=0

We move all terms containing b to the left, all other terms to the right

b=12

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