8/9(y+3)=40

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Solution for 8/9(y+3)=40 equation:



8/9(y+3)=40
We move all terms to the left:
8/9(y+3)-(40)=0
Domain of the equation: 9(y+3)!=0
y∈R
We multiply all the terms by the denominator
-40*9(y+3)+8=0
Wy multiply elements
-360y(y+8=0

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