(1/6)(12z-18)=2z-3

Solution for (1/6)(12z-18)=2z-3 equation:

(1/6)(12z-18)=2z-3

We move all terms to the left:

(1/6)(12z-18)-(2z-3)=0


Domain of the equation: 6)(12z-18)!=0

z∈R


We add all the numbers together, and all the variables

(+1/6)(12z-18)-(2z-3)=0

We get rid of parentheses

(+1/6)(12z-18)-2z+3=0

We multiply parentheses ..

(+12z^2+1/6*-18)-2z+3=0

We multiply all the terms by the denominator


(+12z^2+1-2z*6*-18)+3*6*-18)=0

We add all the numbers together, and all the variables

(+12z^2+1-2z*6*-18)=0

We get rid of parentheses

12z^2-2z*6*+1-18=0

We add all the numbers together, and all the variables

12z^2-2z*6*-17=0

Wy multiply elements

12z^2-12z^2-17=0

We add all the numbers together, and all the variables

-17!=0

There is no solution for this equation